Parse json data to comma separated string in sql server

A question from ASP.NET forum:

SQL Server 2016 or above:


SET @json =   
 {"countryCode":"IN","countryName":"India","postalCode":"400102","administrativeArea":"Maharashtra","subAdministrativeArea":"Mumbai Suburban","locality":"Mumbai","subLocality":"Andheri West","thoroughfare":"New Link Road","subThoroughfare":"2"} ]' 
 SELECT Concat_WS(', ',countryCode,countryName,postalCode,locality,
 administrativeArea) Locations
 FROM   OPENJSON ( @json ) 
 with ( 
 countryCode varchar(10) '$.countryCode',
  countryName varchar(10) '$.countryName',
   postalCode varchar(10) '$.postalCode' ,
   administrativeArea varchar(50) '$.administrativeArea' ,
    locality varchar(50) '$.locality'  

For prior SQL Server 2014 or earlier:
You may try to use a function to do the convert from json to xml. Here is a sample UDF written by DANIEL HUTMACHER.

Here is the link:

Converting JSON data to XML using a T-SQL function

The query to use the UDF and extract data:


SET @json =   
 {"countryCode":"IN","countryName":"India","postalCode":"400102","administrativeArea":"Maharashtra","subAdministrativeArea":"Mumbai Suburban","locality":"Mumbai","subLocality":"Andheri West","thoroughfare":"New Link Road","subThoroughfare":"2"}' 

 ;with mycte as 
SELECT  dbo.fn_parse_json2xml(@json)   myXML

select myxml, 
 S.a.value('(countryCode/text())[1]', 'varchar(15)') 
 as countryCode,
 S.a.value('(countryName/text())[1]', 'varchar(15)') 
 as countryName,
  S.a.value('(postalCode/text())[1]', 'varchar(15)') 
 as postalCode,
  S.a.value('(administrativeArea/text())[1]', 'varchar(15)') 
 as administrativeArea
 ,S.a.value('(locality/text())[1]', 'varchar(15)') 
 as locality
 FROM mycte
CROSS APPLY myXML.nodes('/.') S(a)

THE UDF copied from DANIEL HUTMACHER’s blog to support above code.


CREATE FUNCTION dbo.fn_parse_json2xml(
    @json    varchar(max)

    DECLARE @output varchar(max), @key varchar(max), @value varchar(max),
        @recursion_counter int, @offset int, @nested bit, @array bit,
        @tab char(1)=CHAR(9), @cr char(1)=CHAR(13), @lf char(1)=CHAR(10);

    --- Clean up the JSON syntax by removing line breaks and tabs and
    --- trimming the results of leading and trailing spaces:
    SET @json=LTRIM(RTRIM(
        REPLACE(REPLACE(REPLACE(@json, @cr, ''), @lf, ''), @tab, '')));

    --- Sanity check: If this is not valid JSON syntax, exit here.
    IF (LEFT(@json, 1)!='{' OR RIGHT(@json, 1)!='}')
        RETURN '';

    --- Because the first and last characters will, by definition, be
    --- curly brackets, we can remove them here, and trim the result.
    SET @json=LTRIM(RTRIM(SUBSTRING(@json, 2, LEN(@json)-2)));

    SELECT @output='';
    WHILE (@json!='') BEGIN;

        --- Look for the first key which should start with a quote.
        IF (LEFT(@json, 1)!='"')
            RETURN 'Expected quote (start of key name). Found "'+
                LEFT(@json, 1)+'"';

        --- .. and end with the next quote (that isn't escaped with
        --- and backslash).
        SET @key=SUBSTRING(@json, 2,
            PATINDEX('%[^\\]"%', SUBSTRING(@json, 2, LEN(@json))+' "'));

        --- Truncate @json with the length of the key.
        SET @json=LTRIM(SUBSTRING(@json, LEN(@key)+3, LEN(@json)));

        --- The next character should be a colon.
        IF (LEFT(@json, 1)!=':')
            RETURN 'Expected ":" after key name, found "'+
                LEFT(@json, 1)+'"!';

        --- Truncate @json to skip past the colon:
        SET @json=LTRIM(SUBSTRING(@json, 2, LEN(@json)));

        --- If the next character is an angle bracket, this is an array.
        IF (LEFT(@json, 1)='[')
            SELECT @array=1, @json=LTRIM(SUBSTRING(@json, 2, LEN(@json)));

        IF (@array IS NULL) SET @array=0;
        WHILE (@array IS NOT NULL) BEGIN;

            SELECT @value=NULL, @nested=0;
            --- The first character of the remainder of @json indicates
            --- what type of value this is.

            --- Set @value, depending on what type of value we're looking at:
            --- 1. A new JSON object:
            ---    To be sent recursively back into the parser:
            IF (@value IS NULL AND LEFT(@json, 1)='{') BEGIN;
                SELECT @recursion_counter=1, @offset=1;
                WHILE (@recursion_counter!=0 AND @offset<LEN(@json)) BEGIN;
                    SET @offset=@offset+
                        PATINDEX('%[{}]%', SUBSTRING(@json, @offset+1,
                    SET @recursion_counter=@recursion_counter+
                        (CASE SUBSTRING(@json, @offset, 1)
                            WHEN '{' THEN 1
                            WHEN '}' THEN -1 END);

                SET @value=CAST(
                    dbo.fn_parse_json2xml(LEFT(@json, @offset))
                        AS varchar(max));
                SET @json=SUBSTRING(@json, @offset+1, LEN(@json));
                SET @nested=1;

            --- 2a. Blank text (quoted)
            IF (@value IS NULL AND LEFT(@json, 2)='""')
                SELECT @value='', @json=LTRIM(SUBSTRING(@json, 3,

            --- 2b. Other text (quoted, but not blank)
            IF (@value IS NULL AND LEFT(@json, 1)='"') BEGIN;
                SET @value=SUBSTRING(@json, 2,
                        SUBSTRING(@json, 2, LEN(@json))+' "'));
                SET @json=LTRIM(
                    SUBSTRING(@json, LEN(@value)+3, LEN(@json)));

            --- 3. Blank (not quoted)
            IF (@value IS NULL AND LEFT(@json, 1)=',')
                SET @value='';

            --- 4. Or unescaped numbers or text.
            IF (@value IS NULL) BEGIN;
                SET @value=LEFT(@json,
                    PATINDEX('%[,}]%', REPLACE(@json, ']', '}')+'}')-1);
                SET @json=SUBSTRING(@json, LEN(@value)+1, LEN(@json));

            --- Append @key and @value to @output:
            SET @output=@output+@lf+@cr+
                REPLICATE(@tab, @@NESTLEVEL-1)+
                        REPLACE(@value, '\"', '"'), '\\', '\'), '')+
                    (CASE WHEN @nested=1
                        THEN @lf+@cr+REPLICATE(@tab, @@NESTLEVEL-1)
                        ELSE ''

            --- And again, error checks:
            --- 1. If these are multiple values, the next character
            ---    should be a comma:
            IF (@array=0 AND @json!='' AND LEFT(@json, 1)!=',')
                RETURN @output+'Expected "," after value, found "'+
                    LEFT(@json, 1)+'"!';

            --- 2. .. or, if this is an array, the next character
            --- should be a comma or a closing angle bracket:
            IF (@array=1 AND LEFT(@json, 1) NOT IN (',', ']'))
                RETURN @output+'In array, expected "]" or "," after '+
                    'value, found "'+LEFT(@json, 1)+'"!';

            --- If this is where the array is closed (i.e. if it's a
            --- closing angle bracket)..
            IF (@array=1 AND LEFT(@json, 1)=']') BEGIN;
                SET @array=NULL;
                SET @json=LTRIM(SUBSTRING(@json, 2, LEN(@json)));

                --- After a closed array, there should be a comma:
                IF (LEFT(@json, 1) NOT IN ('', ',')) BEGIN
                    RETURN 'Closed array, expected ","!';

            SET @json=LTRIM(SUBSTRING(@json, 2, LEN(@json)+1));
            IF (@array=0) SET @array=NULL;


    --- Return the output:
    RETURN CAST(@output AS xml);

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