Last datetime (or beginning) of the month, week, and year with sql
Posted: September 18, 2008 Filed under: SQL Server Leave a comment….WHERE checkedintime>DATEADD(s,-1, DATEADD(month, DATEDIFF(month,0,GETDATE()),0)) AND checkedintime< =DATEADD(s,-1, DATEADD(month, DATEDIFF(month,0,GETDATE())+1,0))
–SELECT DATEADD(s,-1, DATEADD(month, DATEDIFF(month,0,GETDATE())+1,0)) as LastDayTime_CurrentMonth
–SELECT DATEADD(s,-1, DATEADD(month, DATEDIFF(month,0,GETDATE()),0)) as LastDayTime_PreviousMonth
DATEADD
(Q, DATEDIFF(Q, 0, getdate()) , 0) as beginningQuarterSELECT
DATEADD(DD, 1– DATEPART(DW, getdate()), DateDiff(day, 0, GETDATE())) as beginningOfThisSundaySELECT
DATEADD(DD, 1– DATEPART(DW, getdate()), 7 + DateDiff(day, 0, GETDATE())) as beginningOfNextSundaySELECT
DATEADD(DD, 1– DATEPART(day, getdate()), DateDiff(day, 0, GETDATE())) as beginningOfThisMonthor
SELECT
DATEADD(mm, DATEDIFF(mm,0,GETDATE())-1,0) as StartOfLastMonth
SELECT
DATEADD(mm, DATEDIFF(mm,0,GETDATE()),0) as StartOfThisMonth
SELECT
DATEADD(mm, DATEDIFF(m,0,GETDATE())+1,0) as StartOfNextMonth
SELECT
DATEADD(day, DATEDIFF(day,0,GETDATE()),0) as StartOftheday
SELECT
DATEADD(day, DATEDIFF(day,0,GETDATE())+1,0) as StartOfNextday
SELECT
DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE())+1,0)) as LastDay_CurrentMonth
SELECT
DATEADD(s,-1, DATEADD(day, DATEDIFF(day,0,GETDATE()),0)) as LastDayTime_PreviousDay
SELECT
DATEADD(s,-1, DATEADD(day, DATEDIFF(day,0,GETDATE())+1,0)) as LastDayTime_CurrentDay
SELECT
DATEADD(s,-1, DATEADD(year, DATEDIFF(year,0,GETDATE()),0)) as LastDayTime_PreviousYear
SELECT
DATEADD(s,-1, DATEADD(year, DATEDIFF(year,0,GETDATE())+1,0)) as LastDayTime_CurrentYear
SELECT
DATEADD(s,-1, DATEADD(week, DATEDIFF(week,0,GETDATE()),0)) as LastDayTime_PreviousWeek
SELECT
DATEADD(s,-1, DATEADD(week, DATEDIFF(week,0,GETDATE())+1,0)) as LastDayTime_CurrentWeek
SELECT
DATEADD(s,-1, DATEADD(month, DATEDIFF(month,0,GETDATE())+1,0)) as LastDayTime_CurrentMonth
SELECT
DATEADD(s,-1, DATEADD(month, DATEDIFF(month,0,GETDATE()),0)) as LastDayTime_PreviousMonth
SELECT
DATEADD(ms,-3, DATEADD(year, DATEDIFF(year,0,GETDATE()),0)) as LastDayTimeOfPreviousYear
SELECT
DATEADD(ms,-3, DATEADD(year, DATEDIFF(year,0,GETDATE())+1,0)) as beginningOfNextYear
Select All (Any) From a DropDownList with range items in ASP.NET
Posted: September 17, 2008 Filed under: ASP.NET 2 Leave a commentSQL part:
Declare
@length decimal(8,1)SET
@length=9.5SELECT
length FROM mylengthWHERE
@length
IS NULL Orlength
>=@length and length < CASE
WHEN
@length= 7.5 THEN 8 WHEN
@length= 8.5 THEN 9 WHEN
@length= 9.5 THEN 10 WHEN
@length= 10.5 THEN 15 WHEN
@length= 15.5 THEN 20 WHEN
@length= 20.5 THEN 25 WHEN
@length= 25.5 THEN 30 WHEN
@length= 30.5 THEN 35 WHEN
@length= 35.5 THEN 45 WHEN
@length= 45.5 THEN 60 WHEN
@length= 60.5 THEN 300 ELSE
1000.0
END
A complete sample ASP.NET page working with the DropDownList:
<asp:DropDownList ID="DropDownListLength" runat="server" AutoPostBack="true" > <asp:ListItem Value="">Any</asp:ListItem> <asp:ListItem Value="0.0">7" and under"</asp:ListItem> <asp:ListItem Value="7.5">7.5" - 8"</asp:ListItem> <asp:ListItem Value="8.5">8.5" - 9"</asp:ListItem> <asp:ListItem Value="9.5">9.5" - 10"</asp:ListItem> <asp:ListItem Value="10.5">10.5" - 15"</asp:ListItem> <asp:ListItem Value="15.5">15.5" - 20"</asp:ListItem> <asp:ListItem Value="20.5">20.5" - 25"</asp:ListItem> <asp:ListItem Value="25.5">25.5" - 30"</asp:ListItem> <asp:ListItem Value="30.5">30.5" - 35"</asp:ListItem> <asp:ListItem Value="35.5">35.5" - 45"</asp:ListItem> <asp:ListItem Value="45.5">45.5" - 60"</asp:ListItem> <asp:ListItem Value="60.5">60.5" Plus</asp:ListItem> </asp:DropDownList> <asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" DataSourceID="SqlDataSource1"> <Columns> <asp:BoundField DataField="id" HeaderText="id" SortExpression="id" /> <asp:BoundField DataField="length" HeaderText="length" SortExpression="length" /> </Columns> </asp:GridView> <asp:SqlDataSource ID="SqlDataSource1" runat="server" ConnectionString="<%$ ConnectionStrings:forumConnectionString %>" CancelSelectOnNullParameter="false" SelectCommand="SELECT [id], [length] FROM [myLength] WHERE @length IS NULL Or (length >@length and length < CASE WHEN @length= 7.5 THEN 8 WHEN @length= 8.5 THEN 9 WHEN @length= 9.5 THEN 10 WHEN @length= 10.5 THEN 15 WHEN @length= 15.5 THEN 20 WHEN @length= 20.5 THEN 25 WHEN @length= 25.5 THEN 30 WHEN @length= 30.5 THEN 35 WHEN @length= 35.5 THEN 45 WHEN @length= 45.5 THEN 60 WHEN @length= 60.5 THEN 300 ELSE 1000.0 END)"> <SelectParameters> <asp:ControlParameter Name="length" ControlID="DropDownListLength" PropertyName="SelectedValue" Type="Decimal" /> </SelectParameters></asp:SqlDataSource>Question asked from here: http://forums.asp.net/p/1321016/2627669.aspx#2627669
Use two languages in the same project with ASP.NET 2.0
Posted: September 15, 2008 Filed under: ASP.NET 2 Leave a comment<codeSubDirectories>
<add directoryName="VBCode" />
</codeSubDirectories>
</compilation>
retrieve Data within this week using SQL
Posted: September 13, 2008 Filed under: SQL Server Leave a commentSET DATEFIRST 7
SELECT DATEADD(DD, 1– DATEPART(DW, getdate()), DateDiff(day, 0, GETDATE())) as beginningOfThisSunday
SELECT DATEADD(DD, 1– DATEPART(DW, getdate()), 7 + DateDiff(day, 0, GETDATE())) as beginningOfNextSunday
SELECT * FROM yourtable WHERE yourDTcolumn>=DATEADD(DD, 1– DATEPART(DW, getdate()), DateDiff(day, 0, GETDATE()))
AND yourDTcolumn<DATEADD(DD, 1– DATEPART(DW, getdate()), 7 + DateDiff(day, 0, GETDATE()))
Extract part of a string by using SQL functions (substring, charindex, reverse and len)
Posted: September 11, 2008 Filed under: SQL Server Leave a commentUPDATE table1
SET Invoice_No2=SUBSTRING([Invoice_No],charindex(‘-‘,Invoice_No)+1,len(Invoice_No)-charindex(‘-‘,Invoice_No) – charindex(‘-‘,REVERSE(Invoice_No)) )